5m^2-21m=0

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Solution for 5m^2-21m=0 equation: 



5m^2-21m=0

a = 5; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·5·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*5}=\frac{0}{10}
=0
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*5}=\frac{42}{10}
=4+1/5
$

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